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SOLVED: 1. (sin 30% + cos 60%) - cot 90% =? 2. (tan 45%)2 - (sec. 0% + cos 0%) =? 3. (sin 45% + cos 45%) (tan 60%) =? 4. (csc 30% - 45%) + sin 90) =?
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Evaluate: cot^2 30 - 2 cos^2 30 - 3/4 sec^2 45 + 1/4 cosec^2 30 - Sarthaks eConnect | Largest Online Education Community
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![Evaluate the following\\[{{\\cot }^{2}}{{30}^{o}}-2{{\\cos }^{2 }}{{60}^{o}}-\\dfrac{3}{4}{{\\sec }^{2}}{{45}^{o}}-4{{\\sec }^{2 }}{{30}^{o}}\\]](https://www.vedantu.com/question-sets/367dd2dc-1495-4d6a-a8b7-abec1906fce23344218817829042201.png "Evaluate the following\\[{{\\cot }^{2}}{{30}^{o}}-2{{\\cos }^{2 }}{{60}^{o}}-\\dfrac{3}{4}{{\\sec }^{2}}{{45}^{o}}-4{{\\sec }^{2 }}{{30}^{o}}\\]")
Evaluate the following\\[{{\\cot }^{2}}{{30}^{o}}-2{{\\cos }^{2 }}{{60}^{o}}-\\dfrac{3}{4}{{\\sec }^{2}}{{45}^{o}}-4{{\\sec }^{2 }}{{30}^{o}}\\]
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Evaluate tan^2 60+4cos^2 45+3cosec^2 60+2cos^2 90 / 2cosec30+3sec60-7/3cot^2 30 - YouTube
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SOLVED: Text: sin cos tan 0 Csc sec 4 cot 213 30" 2 v V3 3 # 459 Vz V2 # 213 V3 608 2 3 Activity: Solve ME! Find the exact
Ex 8.2, 1 (iv) - Evaluate (sin 30° + tan 45° - cosec 60°) / (sec 30° +
evaluate cot sqaure 30 degree- 2 cos square 30 degree- 3/4 sec sqaure 45 + 1/4 cosec sqaure 30 degree - Maths - Introduction to Trigonometry - 5002422 | Meritnation.com
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Show that :2 ( cos^4 60^∘ + sin^4 30^∘ ) - ( tan^2 60^∘ + cot^2 45^∘ ) + 3 sec^2 30^∘ = 14
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